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Q. Which of the following relations are correct?
(A) $\Delta U = q + p \Delta V$
(B) $\Delta G =\Delta H - T \Delta S$
(C) $\Delta S =\frac{ q _\text{ rev }}{ T }$
(D) $\Delta H =\Delta U -\Delta nRT$
Choose the most appropriate answer from the options given below :

JEE MainJEE Main 2023Thermodynamics

Solution:

Only (B) and (C) are correct.
(B) $G = H - TS$
At constant $T$
$\Delta G =\Delta H - T \Delta S$
(A) First law is given by
$\Delta U = Q + W$
If we apply constant $P$ and reversible work.
$\Delta U = Q - P \Delta V$
(C)By definition of entropy changc
$dS =\frac{ dq _\text{ rev }}{ T }$
At constant $T$
$\Delta S =\frac{ q _\text{ rev }}{ T }$
(D) $H = U + PV$
For ideal gas
$H = U + nRT$
At constant $T$
$\Delta H =\Delta U +\Delta nRT$