Question

Which of the following reactions will not give the anhydrous $ AlCl_{3} $ ?

• A. By heating $ AlCl_{3}\,\,6H_{2}O $
• B. By passing dry $ HCl $ gas on heated aluminium powder
• C. By passing dry chlorine gas on heated aluminium powder
• D. By passing dry chlorine gas over a heated mixture of alumina and coke

Answer 1

Answer: (A)

[a] $2AlCl_36H_2O \ce{->[\Delta]} Al_2O_3 + 6HCl \uparrow + 9H_2O \uparrow$
[b] $2Al + \underset{\text{(dry)}}{3HCl} \to 2AlCl_3 + 3H_2 \uparrow$
[c] $2Al + \underset{\text{(dry)}}{3Cl_2} \to 2AlCl_3$
[d] $Al_2O_3 + 3C + 3Cl_2 \to 2AlCl_3 + 3CO \uparrow$