Question

Which of the following reactions will not give pure propane?

• A. $CH_{3}CH_{2}Cl+2Na+ClCH_{3}\overset{e t h e r}{ \rightarrow }$
• B. $CH_{3}CH_{2}CH_{2}COONa\overset{s o d a l i m e}{ \rightarrow }$
• C. $CH_{3}CH=CH_{2}\overset{H_{2} / P d}{ \rightarrow }$
• D. $CH_{3}C\equiv CH\overset{H_{2} / P d}{ \rightarrow }$

Answer 1

Answer: (A)

Here in option A reaction will not give pure propane

$CH_{3}CH_{2}Cl+2Na+ClCH_{2}CH_{3}\overset{d r y e t h e r}{ \rightarrow }CH_{3}CH_{2}CH_{2}CH_{3}+2NaCl$

$CH_{3}Cl+2Na+ClCH_{3}\overset{d r y e t h e r}{ \rightarrow }CH_{3}CH_{3}+2NaCl$

$CH_{3}CH_{2}Cl+2Na+ClCH_{3}\overset{d r y e t h e r}{ \rightarrow }CH_{3}CH_{2}CH_{3}+NaCl$

Thus, we get a mixture containing butane, ethane and propane.

In rest other reaction pure propane is possible.