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Q. Which of the following quantities has the SI unit $kg m ^{2} s ^{-3} A ^{-2} ?$

Physical World, Units and Measurements

Solution:

$\operatorname{kg} m^{2} s^{-3} A^{-2}=\left[M L^{2} T^{-3} A^{-2}\right]$
$=\frac{\left[M L^{2} T^{-2}\right]}{\left[A^{2} T\right]}$
$=\frac{\left[M L^{2} T^{-2}\right]}{[A T][A]}$
$=\frac{\text { Work }}{\text { Charge } \times \text { Current }}$
$=\frac{\text { Voltage }}{\text { Current }}=$ Resistance