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  4. Which of the following particle has the shortest de-Broglie wavelength ?

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Q. Which of the following particle has the shortest de-Broglie wavelength ?

TS EAMCET 2021

Solution:

By using de-Broglie wavelength,
$ \lambda=\frac{h}{p}=\frac{h}{m v} $
$ \lambda \propto \frac{1}{m}$
Since, $\alpha$-particle is the heavier most.
$\therefore \lambda$ of $\alpha$-particle will be least.