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Q. Which of the following orders of ionic radii is correctly represented?

AIPMTAIPMT 2014Classification of Elements and Periodicity in Properties

Solution:

(No option is correct.)
(a) $H^- > H^+ > H$
It is known that radius of a cation is always smaller than that of a neutral number of orbits. Whereas, the radius of anion is always greater than a cation due to decrease in effective nuclear charge. Hence, the correct order is
$ H^- > H^+ > H$
(b) $ Na^+ > F^- > O^{2-}$
The given species are isoelectronic as they contain same number of electrons. For isoelectronic species
Ionic radii $\propto \frac{1}{\text{atomic number}}$
Ion: $ Na^+ > F^- > O^{2-}$
Atomic number: 11 9 8
Hence, the correct order of ionic radii is
$ O^{2-} > F^- > Na^+$
(c) Similarly, the correct option is
$ O^{2-} > F^- > Na^+$
(d) Ions $Al^{3+} > Mg^{2+} > N^{3-}$
Atomic number $ 13 \, \, 12 \, \, \, 7 $
Hence, the correct order is, $N^{3-} > Mg^{2+} > Al^{3+}$