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  4. Which of the following metals in solution forms a precipitate with NaOH, which is not soluble in an excess of the base?

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Q. Which of the following metals in solution forms a precipitate with $ NaOH, $ which is not soluble in an excess of the base?

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Solution:

Iron (Fe) metal in solution forms a red brown precipitate with $ NaOH $ and this precipitate is not soluble in an excess of the base. $ FeC{{l}_{3}}+3NaOH\xrightarrow{{}}\underset{\begin{smallmatrix} \text{ferric}\,\,\text{hydroxide} \\ (red\,\,brown\,\,ppt.) \end{smallmatrix}}{\mathop{Fe{{(OH)}_{3}}}}\,+3NaCl $ While the precipitate of Sn, Pb, Zn and all hydroxides are soluble in the excess of base.