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  4. Which of the following is paramagnetic ?

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Q. Which of the following is paramagnetic ?

BHUBHU 1997Coordination Compounds

Solution:

Ni(Z = 28) : $[Ar]^{18} \, 4s^23d^8$
$ Ni^{2+} : [Ar]^{18}\, 3d^8$
$ [Ni(NH_3)_4]^{2+} : Ni^{2+}$ undergoes $sp^3$-hybridisation, the resulting ion is paramagnetic due to the presence of two unpaired electrons.
$Ni(CO)_4$ : Two $4s$-electrons in Ni pair up with $3d$-electrons followed by $sp^{3}$-hybridisation. The resulting complex has no unpaired electron and is diamagnetic.
$[Ni(CN)_4]^{2-}$ : CN' being a strong ligand, pairs up the two unpaired electrons in $d$-subshell of $Ni^{2+}$.
This is followed by $dsp^2$-hybridisation. The complex ion has no unpaired electron and is diamagnetic.
$[Co(NH_3)_6]^{3+} : Co^{3+}$ with $3d^6$-configuration undergoes $d^2sp^3$-hybridisation, after pairing up of all the six $d$-electrons in three $d$-orbitals. As the ion has no unpaired electron, it is diamagnetic