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Q.
Which of the following is not a function?
J & K CETJ & K CET 2013Relations and Functions
Solution:
$ \because $ $ {{y}^{2}}=x\,\,\,\,\,\Rightarrow \,\,\,\,\,y=\pm \sqrt{x} $
is one value of x gives two values of y. So,
$ \{(x,y):\,x,\in R,\,{{y}^{2}}=x\} $ is not a function.