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Q. Which of the following is correct?

NTA AbhyasNTA Abhyas 2022

Solution:

As the electronegativity order of hybridized carbons is $sp>sp^{2}>sp^{3}$ so in an allylic halide, such as $CH_{2}=CH-CH_{2}-Cl$ , the alpha carbon is much more partially positive than the alpha carbon in(n-propyl chloride) $\text{CH}_{\text{3}} - \text{CH}_{\text{2}} - \text{ CH}_{\text{2}} - \text{Cl}$ . Therefore, the attacking nucleophile will be attracted to the alpha carbon more in the allylic halide compound than in the primary halide. It means allylic halides tend to follow $S_{N 2}$ pathways more than primary halides.
Solution