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  4. Which of the following has the highest bond order ?

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Q. Which of the following has the highest bond order ?

KCETKCET 2006Chemical Bonding and Molecular Structure

Solution:

Molecular orbital configuration of

$N _{2}=14 e^{-}=\sigma 1 s^{2},{ }^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, $

$\sigma 2 p_{x}^{2}, \pi 2 p_{y}{ }^{2}, \pi 2 p_{z}{ }^{2} $

Bond order $=\frac{N_{b}-N_{a}}{2}=\frac{10-4}{2}=3$

Similarly for $O _{2}$ molecule, bond order $=2$

For $ He _{2}$ molecule, bond order $=0$

For $ H _{2}$ molecule bond order $=1$ So, $N _{2}$ has highest bond order.