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Q.
Which of the following has maximum value of cation/anion ratio?
The Solid State
Solution:
Among the three options $KCl , NaCl$ and $MgCl _2$, the size of anion is same. So, larger the cation, larger will be the cation/anion ratio i.e., $KCl$ will have larger cation/anion ratio among the three. So, we left with two options $KCl$ and $CaF _2$. Among these two $CaF _2$ will have maximum value of cation/anion ratio because decrease in ionic radii of anion from $Cl ^{-}$to $F ^{-}$does not overcome the effect of decrease in ionic radii of cation from $K ^{+}$to $Ca ^{2+}$.