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Q.
Which of the following function(s) have no domain?
Relations and Functions - Part 2
Solution:
(A) obviously $x>1$
for $1< x <2,[ x ]=1 \Rightarrow N =0$
for $x \geq 2, N <0 \Rightarrow$ no domain
(B) $0 \leq\{x\}<1$ hence $-1<-\{x\} \leq 0$
hence $1<2-\{x\} \leq 2$
$\Rightarrow \cos ^{-1}(2-\{ x \})$ does not exist. $]$