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Q. Which of the following free radicals is responsible for causing break down of ozone into oxygen due to use of $ CFCs $ ?

JamiaJamia 2015

Solution:

$ E_{cell}^{o}=\frac{0.059}{2}\log {{k}_{c}}=11V $ $ \log {{k}_{c}}=\frac{1.1v\times 2}{0.059v}=37.288 $ $ {{k}_{c}}=2\times {{10}^{37}}at\,298k $ The chlorine radicals are continuously regenerated and cause the breakdown of ozone.