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Q.
Which of the following exhibits the greatest freezing point lowering per mole of solute?
NTA AbhyasNTA Abhyas 2020Solutions
Solution:
Lowering in freezing point is a colligative property, colligative property depends on the number of molecule atom or ions and molality. In 0.1 m NaCl. Molality is maximum out of four and NaCl dissociates into $Na^{+},Cl^{-}$ (i = 2).
Colligative property $ \propto m\times i$
So, 0.1 m NaCl > 0.1 m $C_{2}H_{5}OH$ > 0.01 m NaCl > 0.01 m $C_{2}H_{5}OH$