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Q. Which of the following compounds is likely to show both Frenkel and Schottky defects in its crystalline form ?

JEE MainJEE Main 2020The Solid State

Solution:

Since $AgBr$ has intermediate radius ratio
$\therefore $ it shows both schottky & Frenkel defects
$\ce{ZnS->Frenkel defects}$
$\ce{KBr, CsCl->Schottky defects}$