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Q. Which of the following arrangement is possible?

n l m s
a 5 2 2 $+ 1/2$
b 2 2 0 $-1/2$
c 3 -2 1 $+1/2$
d 0 0 1 $+1/2$

AIIMSAIIMS 2001Structure of Atom

Solution:

For a given value of $n, l = 0$ to $n - 1$;

for a given value of $l, m = -l$ to $+l$ including zero;

for a given value of $m, s =+\frac{1}{2},-\frac{1}{2}$

∴ When $n = 5$, then $l = 0, 1, 2, 3, 4$;

when $l = 2$, then $m = -2, -1, 0, +1, +2$

The value of s can be $±1/2$

Hence, the arrangement, $n = 5, l = 2, m = 2, s = +1/2$

is possible for an electron.