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Q.
Which of the following are paramagnetic tetrahedral species?
Coordination Compounds
Solution:
$\left[ FeCl _{4}\right]^{-}$
$Fe ^{3+} 3 d ^{5} 4 s ^{0} . Cl ^{-}$is a weak ligand. Hence $sp ^{3}$ hybridization occurs. This gives tetrahedral geometry. It is paramagnetic having $5$ unpaired electrons.
$\left[ Ni ( CN )_{4}\right]^{2-}$
$Ni ^{2+} 3 d ^{8} 4 s ^{0} . CN ^{-}$is a strong ligand. Electron pairing takes place and $dsp ^{2}$ hybridization occurs. It is diamagnetic having square planar geometry and has no unpaired electron.
$\left[ NiCl _{4}\right]^{2-}$
$Ni ^{2+} 3 d ^{8} 4 s ^{0} . Cl ^{-}$is a weak ligand. $sp ^{3}$ hybridization occurs. It has tetrahedral geometry and is paramagnetic as it has $2$ unpaired electrons.
$\left[ Zn \left( NH _{3}\right)_{4}\right]^{2+}$
$Zn ^{2+} 3 d ^{10} 4 s ^{0} . sp ^{3}$ hybridization occurs. The complex is tetrahedral but is diamagnetic as it has no unpaired electron.