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Q. Which of the following applies in the reaction,
$CH _{3} CHBrCH _{2} CH _{3} \xrightarrow{ Alc.KOH }$
(i) $CH _{3} CH = CHCH _{3}$ (major product)
(ii) $CH _{2}= CHCH _{2} CH _{3}$ (minor product)

NTA AbhyasNTA Abhyas 2022Haloalkanes and Haloarenes

Solution:

Alkyl halides on heating with alcoholic $KOH$ give dehydrohalogenation reaction to yield alkene. If in reaction, more than one alkenes are formed, then according to Saytzeff, the most highly substituted alkene is the major product.

Solution