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Q. Which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity?

Gujarat CETGujarat CET 2010Coordination Compounds

Solution:

The formula of given compiex are as follows :
(a) Hexammine platinum (IV) chioride $[Pt(NH_3 )_6]Cl_4$
(b) Chioropentammine piatinum (IV) chloride
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, [Pt(NH_3 )_5 Cl]Cl_3$
(c) Dichlorotetrammine platinum (JV) chioride
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, [Pt(NH_3 )_4 Cl_2 ]Cl_2$
(d) Trichlorotriammine piatinum (IV) chioride
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, [Pt(NH_3 )_3 Cl_3 ]Cl$
In aqueous soiution, the complexes ionise as
$\, \, \, \, \, [Pt(NH_3)_6]Cl_4\leftrightharpoons \underbrace{[Pt(NH_3)_6]^{4+}+4Cl^-}_{5\, ions}$
$[Pt(NH_3)_5Cl]Cl_3\leftrightharpoons \underbrace{[Pt(NH_3)_5Cl]^{3+}+3Cl^-}_{4\, ions}$
$[Pt(NH_3)_4Cl_2]Cl_2\leftrightharpoons \underbrace{[Pt(NH_3)_4Cl]^{2+}+Cl^-}_{2\, ions}$
$[Pt(NH_3)_3Cl_3]Cl\leftrightharpoons \underbrace{[Pt(NH_3)_3Cl_3]^++Cl^-}_{2\, ions}$
Trichlorotriammine platinum (IV) chioride gives the minimum number of ions in the soiution. Hence, it has the minimum electricaI conductivity.