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Q. Which is incorrect statement for $XeF_{2}$ ?

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

It acts as a $F^{-}$ donor and forms complexes with covalent fluorides like $PF_{5},AsF_{5}$ and $SbF_{5}$ .

$XeF_{2}+PF_{5} \rightarrow \left[\right.XeF\left]\right.^{+}\left[\right.PF_{6}\left]\right.^{-}$

A. the five electrons pairs form trigonal bipyramid with three lone pairs in equatorial positions. Hence, the structure of $XeF_{2}$ becomes linear in accordance with VSEPR theory.

B. $2XeF_{2}+2H_{2}O \rightarrow 2Xe+4HF+O_{2}$

C. $\left(\right.i\left.\right)$ $XeF_{2}+2HCl \rightarrow 2HF+Xe+Cl_{2}$

$\left(\right.ii\left.\right)$ $XeF_{2}+2KI \rightarrow Xe+2KF+I_{2}$