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Q. Which energy level of $He ^{+}$ has energy equal to ground state energy of H-atom?

Structure of Atom

Solution:

$E_{n}$ for any one electron species $=\frac{E_{1} \times Z^{2}}{n^{2}}$ where $E_{1}$ is ground state energy of $H$ -atom.

For $He ^{+}, E_{n}=\frac{E_{1} \times 2^{2}}{n^{2}}$

As given, $\frac{E_{1} \times 2^{2}}{n^{2}}=E_{1}$

$\therefore n=2$

Thus, $2^{\text {nd }}$ energy level of $He ^{+}$ has energy equal to ground state energy of $H$ -atom.