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Q. Which does not undergo comproportionation reaction?

NTA AbhyasNTA Abhyas 2020Redox Reactions

Solution:

$H_{2}S\uparrow+SO_{2}\uparrow\overset{C o m p r o p o r t i o n a t i o n}{ \rightarrow }S\downarrow+H_{2}O$

$I^{-}\left(\right.aq\left.\right)+IO_{3}^{-}\left(\right.aq\left.\right)+H^{+}\left(\right.aq\left.\right)\overset{C o m p r o p o r t i o n a t i o n}{ \rightarrow }I_{2}+H_{2}O$

$K_{2}MnO_{4}+H^{+}\left(\right.aq\left.\right)\overset{D i s p r o p o r t i o n a t i o n}{ \rightarrow }KMnO_{4}+MnO_{2}\downarrow$

$MnO_{4}^{-}\left(\right.aq\left.\right)+Mn^{2 +}\left(\right.aq\left.\right)\overset{C o m p r o p o r t i o n a t i o n}{ \rightarrow }MnO_{2}\downarrow$