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Q. When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can be written as :
$_{92}U^{235} +\, _{0}n^{1} \to \,_{56}Ba^{141} + \,_{36}Kr^{92} + 3x+Q$ (energy)
where three particles named $x$ are produced and energy $Q$ is released. What is the name of the particle $x$ ?

JEE MainJEE Main 2013Nuclei

Solution:

Nuclear fission equation
$_{92}U^{235} + _{0}n^{1} \to _{56}Ba^{141} + _{36}Kr^{92} + 3_{0}n^{1} + Q$ (energy)
Hence particle $x$ is neutron.