Q.
When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can be written as :
$_{92}U^{235} +\, _{0}n^{1} \to \,_{56}Ba^{141} + \,_{36}Kr^{92} + 3x+Q$ (energy)
where three particles named $x$ are produced and energy $Q$ is released. What is the name of the particle $x$ ?
Solution: