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Q. When two monochromatic lights of frequency, $v$ and $\frac{v}{2}$ are incident on a photoelectric metal, their stopping potential becomes $\frac{V_{S}}{2}$ and $V_{S}$ respectively. The threshold frequency for this metal is :

NEETNEET 2022Dual Nature of Radiation and Matter

Solution:

$hv = W +\frac{ v _{0}}{2} e$
$\frac{ h v}{2}= W + v _{0} e$
on solving we get, $W =3 / 2 h v$
$h _{ o }=3 / 2 hv$
$v _{0}=3 / 2 v$