Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. When the three coins are tossed simultaneously, then the probability of getting one head will be:

Bihar CECEBihar CECE 2005

Solution:

Total number of cases $ n(S)={{2}^{3}}=8 $
Favorable cases
$ =\{(H,T,T),(T,H,T),(T,T,H)\} $
$ n(F)=3 $
$ \therefore $ Required probability $ =\frac{3}{8} $
Alternate Solution:
Probability of getting head in one coin is $ p=\frac{1}{2} $
$ \Rightarrow \,\,\,\,\,q=\frac{1}{2} $
$ \therefore $ Probability of getting one head in three tosses
$ ={{\,}^{3}}{{C}_{1}}{{\left( \frac{1}{2} \right)}^{1}}{{\left( \frac{1}{2} \right)}^{2}} $
$ =3{{\left( \frac{1}{2} \right)}^{3}} $
$ =\frac{3}{8} $