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  4. When the temperature of a gas is raised from 27° C to 90° C, the percentage increase in the rms velocity of the molecules will be

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Q. When the temperature of a gas is raised from $27^{\circ} C$ to $90^{\circ} C$, the percentage increase in the rms velocity of the molecules will be

Kinetic Theory

Solution:

$\frac{C'}{C}=\sqrt{\frac{273+90}{273+27}}=\sqrt{\frac{363}{300}}$
or $\frac{C'}{C}=\sqrt{1.21}=1.1$
or $\frac{C'}{C}-1=0.1$
or $\frac{C'-C}{C} \times 100=0.1 \times 100=10$