Question

When the origin is shifted to the point (2. 3) and then the coordinate axes are rotated through an angle $\frac{\pi}{3}$ in the counter clockw ise sense, then the transformed equation of $3x^2 + 2xy + 3y^2 -18x -22y + 50 = 0 $ is

• A. $3x^2 + 3y^2 - 1 = 0$
• B. $( 6 + \sqrt{3} )x^2 - 2xy + (6 - \sqrt{3} )y^2 - 2 = 0 $
• C. $4x^2 + 2y^2 - 1 = 0 $
• D. $( 6 - \sqrt{3} )x^2 + (6 - \sqrt{3} )y^2 + 2xy = 0 $

Answer 1

Answer: (B)

Correct answer is (b) $( 6 + \sqrt{3} )x^2 - 2xy + (6 - \sqrt{3} )y^2 - 2 = 0 $