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  4. When the load on a wire is slowly increased from 3 to 5 kg wt, the elongation increases from 0.61 to 1.02 mm. The work done during the extension of wire is

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Q. When the load on a wire is slowly increased from $3$ to $5\, kg\, wt$, the elongation increases from $0.61$ to $1.02\, mm$. The work done during the extension of wire is

Mechanical Properties of Solids

Solution:

Work done $=\frac{1}{2} \times$ stretching force $\times$ extension.
Therefore, net work done in increasing the length from
$0.164\,mm$ to $1.02\, mm$ is
$W_{2}-W_{1}=\frac{1}{2} \times 5 \times 9.8 \times 1.02 \times 10^{-3}-\frac{1}{2}\times 3 \times 9.8 \times 0.61 \times 10^{-3}$
$=0.016\, J$