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Q. When the frequency of the $AC$ voltage applied to a series $LCR$ circuit is gradually increased from a low value, the impedance of the circuit

WBJEEWBJEE 2017Alternating Current

Solution:

The impedance of LCR circuit
$Z=\sqrt{R^{2}+\left(\omega_{c}-\frac{1}{\omega_{c}}\right)^{2}}$
Where, $R=$ Resistance
$L=$ Inductance
$C=$ Capacitance
When frequency of AC voltage applied to a series $L C R$ circuit, it will first increase and resonance state $\omega_{L}=\frac{1}{\omega_{c}}$, it will decrease.
In that state $(Z=R)$, it will be minimum.
So, it will first increases and then decreases.