1. Tardigrade
  2. Question
  3. Chemistry
  4. When the following reaction was carried out in a bomb calorimeter, Δ U is found to be - text740 text.0 textkJ/mol of ( textNH) text2 textCN(s) (s) at text300 textK . NH2CN(. s .)+ (3/2)O2 (g) arrow N2 (g)+ CO2 (g)+ H2O(. l .) Calculate textΔH text300 textK for the reaction.

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Q. When the following reaction was carried out in a bomb calorimeter, $\Delta U$ is found to be $- \, \text{740} \text{.0} \, \text{kJ/mol}$ of $\left(\text{NH}\right)_{\text{2}} \text{CN(s)}$ (s) at $\text{300} \, \text{K}$ .

$NH_{2}CN_{\left(\right. s \left.\right)}+ \, \frac{3}{2}O_{2 \left(g\right)} \rightarrow N_{2 \left(g\right)}+ \, CO_{2 \left(g\right)}+ \, H_{2}O_{\left(\right. l \left.\right)}$

Calculate $\text{ΔH}_{\text{300} \, \text{K}}$ for the reaction.

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

$\text{ΔH} \, \text{=} \, \text{ΔU} \, \text{+} \, \text{Δn}_{\text{g}} \text{RT}$

$\text{ΔH} = - 740000 + 0.5 \times 8.3 \times 300 = - 738755 \, \text{J}$