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Q. When the electron of a hydrogen atom jumps from $n = 4$ to $n = 1$ state, the number of spectral lines emitted is

AMUAMU 2010Structure of Atom

Solution:

When an electron jumps from $n$ to ground state (ie, $n=1$ ),
the number of spectral lines $=\frac{n(n-1)}{2}$
$\therefore $ When an electron jumps from $n=4$ level number of spectral lines $=\frac{4(4-1)}{2}$
$=\frac{4 \times 3}{2}=6$