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  4. When the distance between two charged particles is halved. The coulomb force between them becomes :

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Q. When the distance between two charged particles is halved. The coulomb force between them becomes :

Haryana PMTHaryana PMT 2000

Solution:

Earlier force between two particles is
$F =\frac{ kq _{1} q _{2}}{ r ^{2}}$
When distance is halved force becomes
$F '=\frac{ kq _{1} q _{2}}{( r / 2)^{2}}=4 \frac{ kq _{1} q _{2}}{ r ^{2}}=4 F$