Q. When resonance is produced in a series $LCR$ circuit, then which of the following is not correct?
Solution:
If $f_0$ is the resonance frequency corresponding to resonant angular frequency $\omega_0$, then $f_0 = \frac{\omega_0}{2 \pi} = \frac{1}{2 \pi \sqrt{LC}} \left( \because \, \omega_0 = \frac{1}{\sqrt{LC}} \right)$
The above eqn. is called the condition for resonance in the $LCR$ circuit. Figure shows the variation of current with frequency of the source. It follows that for $f = f_0$, the current in the circuit is maximum and hence, impedance of the circuit is minimum.
