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Q. When one end of the capillary is dipped in water, the height of water column is ‘$h$’. The upward force of $105 $ dyne due to surface tension is balanced by the force due to the weight of water column. The inner circumference of the capillary is
(Surface tension of water = $7 \times 10^{-2} N/m$)

MHT CETMHT CET 2017

Solution:

Upward force acting $F =105$ dyne
$ =105 \times 10^{-5} N$
Surface tension of water $T =7 \times 10^{-2} N / m$
Surface tension acts at the circumference $C$ of the capillary tube.
$\therefore F = CT$
Or $105 \times 10^{-5}= C \times 7 \times 10^{-2}$
Or $C =15 \times 10^{-3} m$
$\Rightarrow C =15 \times 10^{-1}\, cm =1.5\, cm$