1. Tardigrade
  2. Question
  3. Chemistry
  4. When neutral or faintly alkaline KMnO4 is treated with potassium iodide, iodide ion is converted into 'X'. 'X' is -

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. When neutral or faintly alkaline $KMnO_4$ is treated with potassium iodide, iodide ion is converted into 'X'. 'X' is -

NEETNEET 2019The d-and f-Block Elements

Solution:

$KMnO_4 + I^- + OH^- \rightarrow \underset{(X)}{MnO_2 + IO_3^- + H_2O}$