Question

When $NaNO_{3}$ is heated in a closed, oxygen is liberated and $NaNO_{2}$ is is left behind. At equilibrium

• A. addition of $NaNO_{2}$ favours forward reverse reaction
• B. addition of $NaNO_{2}$ favours forward reaction
• C. increasing temperature favours forward reaction
• D. decreasing pressure favours reverse reaction

Answer 1

Answer: (C)

$NaNO_{3}\left(\right.s\left.\right)\rightleftharpoonsNaNO_{2}\left(\right.s\left.\right)+\frac{1}{2}O_{2}\left(\right.g\left.\right);\Delta H=+ve$
Also $K_{p}=\left(\right.P_{O_{2}}\left(\left.\right)^{1 / 2}$ and thus, addition of $NaNO_{3}$ or $NaNO_{2}$ has no effect.