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  4. When n-butane is heated in the presence of AlCl3/HCl it will be converted into

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Q. When $n$-butane is heated in the presence of $AlCl_3/HCl$ it will be converted into

Hydrocarbons

Solution:

$CH_3-CH_2.CH_2.CH_3 \xrightarrow[HCl]{AlCl_3} CH_3-\underset{\overset{|}{C}{H_3}}{C}H.CH_3$