1. Tardigrade
  2. Question
  3. Chemistry
  4. When metal X is treated with sodium hydroxide, a white precipitate (A) is obtained, which is soluble in excess of NaOH to give soluble complex (B) Compound (A) is soluble in dilute HCl to form compound ( C ). The compound (A) when heated strongly gives (D), which is used to extract metal. The compound (D) is

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Q. When metal $X$ is treated with sodium hydroxide, a white precipitate $(A)$ is obtained, which is soluble in excess of $NaOH$ to give soluble complex $(B)$ Compound $(A)$ is soluble in dilute $HCl$ to form compound $( C )$. The compound $(A)$ when heated strongly gives $(D)$, which is used to extract metal. The compound $(D)$ is

The p-Block Elements

Solution:

The given data suggests that the metal $X$ is aluminium
$\underset{(X)}+3NaOH \to \underset{\text{White gelatinous ppt. (A)}}{{Al(OH)_{3}}} \xrightarrow[{NaOH}]{\text {Excess}} \underset{\text{Sodium tetrahydroxo aluminate (III) (soluble, B)}}{{Na^{+}[Al(OH)_{4}]^{-}}}$
$\underset{(A)} {Al ( OH )_{3}}+3 HCl \longrightarrow \underset{(c)}{AlCl _{3}}+3H _{2} O$
$\underset{(A)}{2Al (OH )_{3}} \xrightarrow{\Delta} \underset{(D)}{Al _{2} O _{3}}+3H _{2}O$