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Q. When isobutene is monochlorinated in the presence of ultraviolet light, the product obtained in higher yield is

Hydrocarbons

Solution:

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$\frac{\% \text { of isobutyl chloride }}{\% \text { of } \text { tert-butyl chloride }}=\frac{\text { no. of primary } H }{\text { no. of tertiary } H } \times \frac{\text { reactivity of } 1^{\circ} H }{\text { reactivity of } 3^{\circ} H }=\frac{9}{1} \times \frac{1}{5}=\frac{9}{5}$
$\%$ of isobutyl chloride $=\frac{9}{9+5} \times 100=74.3 \%$
$\%$ of tert-butyl chloride $=\frac{9}{14} \times 100=25.7 \%$