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Q.
When iron is rusted, it is
Redox Reactions
Solution:
$Fe ( s ) \rightarrow Fe ^{2+}+2 e ^{-}$(Oxidation)
$O _2+4 H ^{\oplus}+4 e ^{-} \rightarrow 2 H _2 O$ (Reduction)
Atmospheric oxidation:
$2 Fe ^{2+}+2 H _2 O +\frac{1}{2} O _2 \rightarrow Fe _2 O _3+4 H ^{\oplus}$
Rust is $Fe _2 O _3 x H _2 O$
Corrosion or rusting occurs in the presence of water and air