Question

When $Fe _{0.93} O$ is heated in presence of oxygen, it converts to $Fe _2 O _3$. The number of correct statement/s from the following is
A. The equivalent weight of $Fe _{0.93} O$ is Molecular wejght
$0.79$
B. The number of moles of $Fe ^{2+}$ and $Fe ^{3+}$ in 1 mole of $Fe _{0.93} O$ is $0.79$ and $0.14$ respectively
C. $Fe _{0.93} O$ is metal deficient with lattice comprising of cubic closed packed arrangement of $O ^{2-}$ ions
D. The $\%$ composition of $Fe ^{2+}$ and $Fe ^{3+}$ in $Fe _{0.93} O$ is $85 \%$ and $15 \%$ respectively

Answer 1

A : $Fe _{0.93} O \rightarrow Fe _2 O _3 $
$ nf =\left(3-\frac{200}{93}\right) \times 0.93$
$ nf =0.79 $
B: $2 x+(0.93-x) \times 3=2 $
$ x=0.79 $
$ Fe ^{2+}=0.79, Fe ^{3+}=0.21$
C : Fact
D : $\% Fe ^{2+}=\frac{0.79}{0.93} \times 100=85 \% ; Fe ^{3+}=15 \% $