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  4. When ethyl iodide and n-propyl iodide are allowed to react with sodium in the presence of dry ether, the number of alkanes that would be produced is

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Q. When ethyl iodide and n-propyl iodide are allowed to react with sodium in the presence of dry ether, the number of alkanes that would be produced is

NTA AbhyasNTA Abhyas 2020Hydrocarbons

Solution:

When ethyl iodide and n-propyl iodide are allowed to react with sodium in the presence of dry ether, the number of alkanes that would be three as follows

$2CH_{3}-CH_{2}-I\overset{N a}{ \rightarrow }CH_{3}-CH_{2}-CH_{2}-CH_{3}$

$2CH_{3}-CH_{2}-CH_{2}-I\overset{N a}{ \rightarrow }\underset{n - h e x a n e}{C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3}}$

$CH_{3}-CH_{2}-I+CH_{3}-CH_{2}-CH_{2}-I\overset{N a}{ \rightarrow }\underset{n - p e n t a n e}{C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{3}}$