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Q. When ethyl alcohol reacts with $ Cl_{2} $ in presence of $ NaOH, $ the product will be

BHUBHU 2007

Solution:

When ethyl alcohol reacts with chlorine gas in presence of $NaOH$, the product will be chloroform
$C _{2} H _{5} OH + Cl _{2} \ce{->[{ NaOH }][{\Delta}]} CHCl _{3}$