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Q. When ethyl alcohol and acetic acid mixed together in equimolecular proportions, equilibrium is attained when two-third of the acid and alcohol are consumed. The equilibrium constant of the reaction will be

Equilibrium

Solution:

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$K_c = \frac{\frac{2}{3}\times \frac{2}{3}}{\frac{1}{3}\times\frac{1}{3}} = 4$ [Considering 1L container]