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Q. When electricity is passed through a solution of $AlCl_{3}, 13.5$ g of $Al$ is discharged. The amount of charge passed is $(Al = 27)$

Electrochemistry

Solution:

$Al^{+3} +3e^{-} \to Al$
$27g$
$1 mole \,\, 3moles$
$1/2 \,\,\,3/2=1.5 F$