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  4. When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be

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Q. When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be

Current Electricity

Solution:

Resistance of bulb $R=\frac{V^{2}}{P}$, where $V$ is the marked voltage and $P$ is the marked power. $P$ is same for both. As both bulbs are connected in series, so current in both of them will be same. So, brightness $\propto R \propto V^{2}$.