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  4. When concentration of reactants in reaction A→ B is increased by 8 times the rate increases only 2 times, the order of the reaction would be

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Q. When concentration of reactants in reaction A$\to$ B is increased by 8 times the rate increases only 2 times, the order of the reaction would be

Chemical Kinetics

Solution:

$r _{1}= k [ A ]^{ n }$

$r _{2}= r _{1}= k [ 8 A ]^{ n }$

$\therefore \frac{ 2 r _{1}}{ r _{1}}=( 8 )^{ n }$

$(2)^{1}=(2)^{3 n }$

$\therefore 3 n =1$

$n =\frac{ 1 }{ 3 }$