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  4. When CHCl3 is boiled with NaOH , it gives

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Q. When $ CHCl_3 $ is boiled with $ NaOH $ , it gives

AMUAMU 2019

Solution:

$CHCl_{3}+4NaOH(aq) \to \underset{\text{Sodium formate}}{{HCOONa}}+3NaCl+2H_{2}O$