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  4. When CH2=CH-COOH is reduced with LiAlH4 , the compound obtained will be

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Q. When $CH_{2}=CH-COOH$ is reduced with $LiAlH_{4}$ , the compound obtained will be

NTA AbhyasNTA Abhyas 2022

Solution:

$CH_{2}=CH-COOH\overset{L i A l H_{4 \, }}{ \rightarrow }$ $CH_{2}=CH-CH_{2}OH+H_{2}O$
LiAlH4 cannot reduce C = C in ether.